6x^2-150x+625=0

Solution for 6x^2-150x+625=0 equation:

6x^2-150x+625=0

a = 6; b = -150; c = +625;
Δ = b2-4ac
Δ = -1502-4·6·625
Δ = 7500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7500}=\sqrt{2500*3}=\sqrt{2500}*\sqrt{3}=50\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-50\sqrt{3}}{2*6}=\frac{150-50\sqrt{3}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+50\sqrt{3}}{2*6}=\frac{150+50\sqrt{3}}{12}
$